this is OK .,.but different input !! 16bit -0x4B0 1.2V ?
try find any easy offsets - 8bit 00 / 01 for verification
this is OK .,.but different input !! 16bit -0x4B0 1.2V ?
try find any easy offsets - 8bit 00 / 01 for verification
But things I am trying to is not on/off stuff to be just 00 or 01 or I am not understanding something here?
Edit: Current settings are 1.4V
this is OVERCLOCK/MEMORY/VDD setup ânow in defaults 1.2Vâ
try in offset map find âM.I.T. + vddâ this you using normally ?
your bios have more identical options
The one that works is 0x14B9
0x30D4F Numeric: DRAM Voltage (CH A/B), VarStoreInfo (VarOffset/VarName): 0x14B9, VarStore: 0x1, QuestionId: 0xE6, Size: 2, Min: 0x0, Max 0xFFFF, Step: 0x1 {07 94 BD 04 C0 04 E6 00 01 00 B9 14 10 11 00 00 FF FF 01 00}
65535 - gigabite defaults number ?
unfortunately I donât know,., my bios has only one option " from OVERCLOCK/MEMORY/VDD"
use offsets that donât work in AMIBCP for better OC
, but you probably wonât overcome the 1.4V limit on ram
also donât risk burned mobo !!!
Default is 0, but optimal is 65535
Kinda weird
There are 6 options only when in bios setup:
Auto, Normal, 1.200V, 1.250V, 1.350V, 1.400V
So I am assuming from 0x0 to 0x5 there are 6 settings. If I tick 6 (7th option which is not there) what could happen?
or your setting 1452465?
but I really donât know what happens if you change this number - to 1.6V or 1.3V or what this number indicates
75535 - 1.65 / or 55535 -1.25 V ?? really do not know
also 65535 - is in AMIBCP - evrivhere under M.I.T. domain
recommended basic tuning ,.,.not risk burned mobo !!
,.,.use extra options for OC âbut this modding is dangerousâ
Hold on a second I will post what changes when I set from Auto to 1.400V all options we probably can guess from there
try 1.2V in MIT -verify this gigabite nuber - 55535 ?
Like I guessed .
Auto #1 option translate to 00
Normal #2 option translate to 01
1.200V #3 option translate to 02
1.250V #4 option translate to 03
1.350V #5 option translate to 04
1.400V #6 option translate to 05
The input is numeric have min 0x0 and max 65535, but default is 0 which is auto even tho there is crazy amount of possible inputs here from 0x0 to 65535 the bit here correspond to the order of the option which in itâs turn means auto, normal, 1.2âŚetc
I will show off screenshots
this is on Auto #1 option bit is 0x0
this is on Normal #2 option bit is 0x1
this is on 1.200V #3 option bit is 0x2
this is on 1.250V #4 option bit is 0x3
this is on 1.350V #5 option bit is 0x4
finally this is on 1.400V #6 option bit is 0x5
so trying 0x6 makes sense right?
ok .,.but how unlock 1.4+ "option â6"7"8â
or what you see in M.I.T. 65535 ??? for â5â
it just depends on what it follows ,.,.but variable is possible RESET âCMOS resetâ
well, the thing is where these options comes from. I mean how they are shown
I donât understand what you mean about âwhat you see in M.I.T, 65535 for 5â
I will try. whatever happens fk it
how look M.I.T. tab ?
i seen only from dump âprobarly bad numbersâ ,.,.you must read actual numbers
you see only options Auto, Normal, 1.200V, 1.250V, 1.350V, 1.400V ?? not this numbers 65535 or similar ??